Program: Implement Binary search in java using divide and conquer technique.
A binary search or halfinterval search algorithm finds the position of a specified value (the input "key") within a sorted
array. In each step, the algorithm compares the input key value with the key value of the middle element of the array. If the keys match,
then a matching element has been found so its index, or position, is returned. Otherwise, if the sought key is less than the middle element's
key, then the algorithm repeats its action on the subarray to the left of the middle element or, if the input key is greater, on the
subarray to the right. If the remaining array to be searched is reduced to zero, then the key cannot be found in the array and a special
"Not found" indication is returned.
Every iteration eliminates half of the remaining possibilities. This makes binary searches very efficient  even for large
collections.
Binary search requires a sorted collection. Also, binary searching can only be applied to a collection that allows random
access (indexing).
Worst case performance: O(log n)
Best case performance: O(1)
package com.java2novice.algos;
public class MyBinarySearch {
public int binarySearch(int[] inputArr, int key) {
int start = 0;
int end = inputArr.length  1;
while (start <= end) {
int mid = (start + end) / 2;
if (key == inputArr[mid]) {
return mid;
}
if (key < inputArr[mid]) {
end = mid  1;
} else {
start = mid + 1;
}
}
return 1;
}
public static void main(String[] args) {
MyBinarySearch mbs = new MyBinarySearch();
int[] arr = {2, 4, 6, 8, 10, 12, 14, 16};
System.out.println("Key 14's position: "+mbs.binarySearch(arr, 14));
int[] arr1 = {6,34,78,123,432,900};
System.out.println("Key 432's position: "+mbs.binarySearch(arr1, 432));
}
}

