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How to create Json Object using Streaming Model API?


This page shows how to create Json object using Streaming API Model.

Note: Refer How to read Json data using JsonReader? page for dependent libraries.

Java example to create json object using generator:

package com.javaapi.json.examples;

import java.io.StringWriter;

import javax.json.Json;
import javax.json.stream.JsonGenerator;

public class CreateJsonObjGenEx {

	public static void main(String a[]){
		
		StringWriter strWtr = new StringWriter();
		JsonGenerator jsonGen = Json.createGenerator(strWtr);
		JsonGenerator start = jsonGen.writeStartObject();
		start.write("emp_name", "Nataraj G");
		start.write("emp_id", 1016);
		start.write("salary", 20000);
		start.writeEnd();
		jsonGen.close();
		
		System.out.println(strWtr.toString());
	}
}

Output:
{"emp_name":"Nataraj G","emp_id":1016,"salary":20000}
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Java API for JSON processing examples

  1. How to read Json data using JsonReader?
  2. How to read Json array data using JsonArray?
  3. How to create Json Object using Object Model?
  4. How to create Json Array using Object Model?
  5. How to create Json Object using Streaming Model API?
  6. How to create Json Array using Streaming Model API?
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About Author

I'm Nataraja Gootooru, programmer by profession and passionate about technologies. All examples given here are as simple as possible to help beginners. The source code is compiled and tested in my dev environment.

If you come across any mistakes or bugs, please email me to [email protected].

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Reference: Java™ Platform Standard Ed. 7 - API Specification | Java™ Platform Standard Ed. 8 - API Specification | Java is registered trademark of Oracle.
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